Question

angle abc=79 degree angle acb = 21 degree.find angle bdc​

Answer 1

Answer:

hope it helps u

Step-by-step explanation:

In ΔABC,

∠BAC + ∠ABC + ∠ACB = 180° (Angle sum property of a triangle)

⇒ ∠BAC + 69° + 31° = 180°

⇒ ∠BAC = 180° − 100º

⇒ ∠BAC = 80°

∠BDC = ∠BAC = 80° (Angles in the same segment of a circle are equal)

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Answer 2

Answer: 80°

Step-by-step explanation:

We know, according to Angle sum property, Angle ABC + Angle BCA + Angle BAC = 180°

Angle ABC = 79°

Angle BCA = 21°

So, 79° + 21° + Angle BAC = 180°

100° + Angle BAC = 180°

Angle BAC = 180° - 100°

Angle BAC = 80°

Hope it Helpd