angle abc and angle bdc are right angle triangle angle bac=90 degree and ac=bd prove that angle abc congruent angle bdc
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Answer:
In △APB and △DPC, we have
∠A=∠D=90
∘
and
∠APB=∠DPC [Vertically opposite angles]
Thus, by AA-criterion of similarity, we have
△APB∼△DPC
⇒
DP
AP
=
PC
PB
⇒ AP×PC=DP×PB
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