Question

angle ABC = angle ACB, AD ids the bisector of angle BAC and AD meets BC at D. show that BD = CD? solve ​

Answer 1

Answer:

anc

Step-by-step explanation:

abc = 56677899099900

Answer 2

Given : angle ABC = angle ACB,

AD is the bisector of angle BAC and

AD meets BC at D.

To Find : show that BD = CD

Solution:

in ΔABD and ΔACD

∠ABD = ∠ACD  as  ∠ABC = ∠ACB   is given and D lies on BC

AD = AD  common side

∠BAD = ∠CAD    = ∠ BAC/2   bisector of angle BAC

=>   ΔABD ≅ ΔACD   (AAS)

=> BD = CD  Corresponding sides of congruent triangles

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