Question

Angle ABC = angle DCB = 90° AB = 6 , DC = 8 then area of triangle ABC upon area of triangle DCB

Answer 1

consider
ABC is a triangle and
DCB is a triangle
then bases of both triangles are same

$\frac{ABC}{DCB} = \frac{6}{8} \\ = \frac{3}{4}$
I think this helps u

Answer 2

Answer:frAB/DC

Explanation:Δwith equal base