Angle ABC is an equilateral triangle. If AB//CE, prove that angle ACE = angle ECD.
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The proof is as follows:
Given:
Triangle ABD and Triangle ACE are equilateral triangles.
To Prove:−
∠ CAD = ∠ BAE
CD =BE
Proof:−
∠ CAD = ∠ CAB + ∠BAD
∠ CAD =∠ CAB + 60° (Since ∠ BAD=60°)
∠CAD = ∠ CAB + ∠ CAE (Since ∠ CAE=60°)
∠ CAD =∠BAE
Hence Proved.
In Triangle CAD and Triangle BAE
BA = AD
Angle CAD = Angle BAE (Proved above)
AC = AE
Triangle CAD ≅ Triangle BAE
So, CD = BE
Hence Proved.
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