angle ABC is isosceles with the length of AB equal to the length of AC. The measure of angle A is 40* and points B,C, and D are collinear. What is the measure of Angle Acd
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Hi Pal here is ur answer
Given: AB=AC
so <B=<C[angles opposite to equal sides are equal]
<A=40°
<A+<B+<C=180°[angle sum property]
40°+x+x=180°
2x=180°-40°
x=140°/2
x=70°=<B=<C
<BCA+<ACD=180°[ linear pair]
70°+y=180°
y=180°-70°
y=110°=<AND
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