Accountancy, asked by llcartoonll, 2 months ago

angle ABC is such that AB is equal to 3cm, bc is equal to 2cm and ca i equal to 2.5cm, if angle DEF angle ABC and EF is equal to 44cm, then perimeter of angle DEF is.
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Answers

Answered by Anonymous
13

Given :

AB = 3cm, BC = 2cm, and CA = 2.5cm, and EF = 4cm.

Also, \rm ΔABC ≈ ΔDEF ΔABC≈ΔDEF

Thus, \large\rm\frac{ AB}{DE}

= \large\rm\frac{BC}{EF}

= \large\rm\frac{AC}{DF}\times\large\rm\frac{3}{DE}=\large\rm\frac{2}{4}=\large\rm\frac{2.5}{DF}

Hence, DE = 6cm and DF = 5cm

Perimeter of \text{ ΔDEF = DE+EF+EF }

\text{ =4+5+6 }

\text{ =15cm }

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Therefore, Perimeter of \rm{ ΔDEF \: = \: 15cm }

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