Question

angle ABC is such that AB is equal to 3cm, bc is equal to 2cm and ca i equal to 2.5cm, if angle DEF angle ABC and EF is equal to 44cm, then perimeter of angle DEF is.
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Answer 1

Given :

AB = 3cm, BC = 2cm, and CA = 2.5cm, and EF = 4cm.

Also, $\rm ΔABC ≈ ΔDEF ΔABC≈ΔDEF$

Thus, $\large\rm\frac{ AB}{DE}$

= $\large\rm\frac{BC}{EF}$

= $\large\rm\frac{AC}{DF}\times$$\large\rm\frac{3}{DE}$=$\large\rm\frac{2}{4}$=$\large\rm\frac{2.5}{DF}$

Hence, DE = 6cm and DF = 5cm

Perimeter of $\text{ ΔDEF = DE+EF+EF }$

$\text{ =4+5+6 }$

$\text{ =15cm }$

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Therefore, Perimeter of $\rm{ ΔDEF \: = \: 15cm }$