Question

Angle ABC of triangle ABC is 45 degree if AC ,/AB is √2 then angle BAC is

Answer 1

Answer:

105 °

Step-by-step explanation:

1. We have AC/AB=
2. $\sqrt{2}$
3. let ACB Be
4. $\alpha$
5. then
6. $\sin(45) \div ac = \sin( \alpha ) \div ab$
7. $1 \div \sqrt{2 } = \sin( \alpha ) \times ac \div ab$
8. $\sin( \alpha ) = 1 \div 2$
9. $but \: \sin(30) = 1 \div 2$
10. $threfore \: \alpha = 30$
11. acb=30°
12. therefore BAC=105°