angle acb=90 and ad=bd ca=12cm and cd=6.5cm find area of triangle ACB
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as it is a right angle triangle with angle ACB = 90 degree
Also it is given that, Sides AC = 12 Cm
And CD = 6.5 Cm
We know in a right angle triangle
Area = 1/2 * (Base * Hiegth)
In triangle ABC,
Area = 1/2 * 12 * 6.5
= 0.5 * 12 * 6.5
= 39 Cm^2
So the area is 39 Cm^2
Also it is given that, Sides AC = 12 Cm
And CD = 6.5 Cm
We know in a right angle triangle
Area = 1/2 * (Base * Hiegth)
In triangle ABC,
Area = 1/2 * 12 * 6.5
= 0.5 * 12 * 6.5
= 39 Cm^2
So the area is 39 Cm^2
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