Question

angle ACD is an exterior angle of angle ABC. If LA=50' and LB = 65then find angle ACD and angle ACB in which chapter this question is NCERT​

Answer 1

Answer:

angle ACD = 115°, angle ACB = 65°

Step-by-step explanation:

LA = 50°

LA = 50° LB = 65°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°Sum of a triangle = 180°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°Sum of a triangle = 180° angle ABC + angle BAC + angle ACB = 180°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°Sum of a triangle = 180° angle ABC + angle BAC + angle ACB = 180°65° + 50° + angle ACB = 180°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°Sum of a triangle = 180° angle ABC + angle BAC + angle ACB = 180°65° + 50° + angle ACB = 180°115° + angle ACB = 180°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°Sum of a triangle = 180° angle ABC + angle BAC + angle ACB = 180°65° + 50° + angle ACB = 180°115° + angle ACB = 180°angle ACB = 180° - 115°

LA = 50° LB = 65°A/Q, Exterior angle = Sum of another opposite angle angle ACD = angle ABC + angle BAC angle ACD = 65° + 50° angle ACD = 115°Sum of a triangle = 180° angle ABC + angle BAC + angle ACB = 180°65° + 50° + angle ACB = 180°115° + angle ACB = 180°angle ACB = 180° - 115°angle ACB = 65°