Angle ACD is an exterior angle of triangle ABC the measures of angle a and b are equal measure of angle ACD equals to 140 degrees find the measure of angles a and b
Answers
a+b=140 (sum of two interior angle of triangle is equal to exterior angle )
a+a=140(since a=b)
2a=140
a=70
∠a = ∠b = 70°
Given:
Angle ACD is an exterior angle of triangle.
ABC the measures of angle a and b are equal measure of angle.
Angle ACD equals to 140 degrees.
To find:
The measure of angles a and b
Concept used:
Sum of any two angles of triangles = Exterior angle of third angle of triangle.
Explanation:
ABC the measures of angle a and b are equal measure of angle.
Sum of any two angles of triangles = Exterior angle of third angle of triangle.
Angle ACD is an exterior angle of triangle. it is exterior angle of third angle of triangle.
So, ∠a+∠b = 140°
∠a + ∠a = 140°
2∠a = 140°
∠a = 70°
Given a and b are equal measure of angle.
∠a = ∠b = 70°
To learn more...
1)The areas of two similar trangles are 100 cm^2 and 64 cm^2 and altitude of first triangle is 20cm then find corresponding altitude of second triangle
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2)Find the value of c
if in a trangle
S= 13, a=8, b=7
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