Question

Angle ACD is and exterior angle of ABC, angle a is 3x, ange acd is 5x, and angle b is 50. what is the value of x?

Answer 1

Answer:

In the isosceles triangle ABC. <A and <B are equal. <ACD is an exterior angle of ABC. The measures of <ACB and <ACD are (3x- 17) and (8x+10), respectively. What are the values of <ACB and <ACD and <A and <B?

<ACB +<ACD = (3x- 17) +(8x+10) = 180, or

11x-7 = 180, or

11x = 187, or

x = 17.

So <ACB =51–17 = 34 deg, and <ACD = 136+10 = 146 deg.

<A = <B = (180–34)/2 = 146/2 = 73 deg.

<ACB = 34 deg, <ACD = 146 deg, <A =<B = 73 deg.