angle ACP = 40° and angle BPD = 120° , FIND angle CBD
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∠CBD = 20°
Step-by-step explanation:
∠BPD = ∠ACP = 40° [angle in same segment]
Now, in △BPD, we have
∠PBD + ∠BPD + ∠BDP = 180°
⇒ ∠PBD + 120° + 40° = 180°
⇒ ∠PBD = 180° - 160° = 20°
or ∠CBD = 20°
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Answer:
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Step-by-step explanation:
1. opposite angles are equal so angle APC is equal to 120
2. sum of all angles of triangle is 180
so 40 +120+angleCAP is equal to 180
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