Angle aob=130 where o is the center of circle. Find anglebco and anglebdc
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Total of angles in a circle is 360
So, aob = 130
360 - 130 = 230 degree
therefore, bco and bdc together makes 230 degree.
and 230/2 = 115
bco = 115
bdc = 115
So, aob = 130
360 - 130 = 230 degree
therefore, bco and bdc together makes 230 degree.
and 230/2 = 115
bco = 115
bdc = 115
Answered by
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Total angel of in a circle is 360
and aob 130
so 360-130=230
solve it 230/2=115
so angle of bdc is=115 is correct answer. !
and aob 130
so 360-130=230
solve it 230/2=115
so angle of bdc is=115 is correct answer. !
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