angle aob=70°find m(arcAXB)
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Answer:
35°
Step-by-step explanation:
From the figure we know that the radius is
OA=OC
We know that the base angles of an isosceles triangle are equal
∠OAC=∠OCA
It is given that ∠OCA=35
o
So we get
∠OAC=35
o
Therefore, ∠OAC=35
o
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