Angle AOC = 6x, Angle OCB = x -10, Angle OAB = x + 30. Work out the value of x.
Would be very grateful for the help,
Thanks.
Attachments:
Answers
Answered by
1
ANGLE ABC=3X
interior angle =360-6x
acc to angle sum property of quad
3x+360-6x+x+30+x-10=360
-x+380=360
-x=360-380
-x=-20
×=20
interior angle =360-6x
acc to angle sum property of quad
3x+360-6x+x+30+x-10=360
-x+380=360
-x=360-380
-x=-20
×=20
karan2711:
is it correct
hm, I'm not sure because 6x is on the outside of the quad, only the interior angles add up to 360 degrees
ya i m sorry
now it is correct
thanks bro thats the one
my pleasure
Similar questions