Angle aoc is x+15 and angel boc is 3x+25 and aob is straight line find angel aoc and angle boc
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x+15+3x+25=180
4x+40=180
4x=180-40
4x=140
x=140/4
x=35
angle aoc=35+15=50
angle boc=3(35)+25=130
4x+40=180
4x=180-40
4x=140
x=140/4
x=35
angle aoc=35+15=50
angle boc=3(35)+25=130
Answered by
2
Angle AOC = x+15
Angle BOC = 3x+25
x+15+3x+25 = 180
4x+40 = 180
4x = 180-40 = 140
x = 140/4 = 35
Angle AOC = 35+15 = 50
Angle BOC = 3×35+25 = 130
HOPE IT HELPS YOU!!!
Angle BOC = 3x+25
x+15+3x+25 = 180
4x+40 = 180
4x = 180-40 = 140
x = 140/4 = 35
Angle AOC = 35+15 = 50
Angle BOC = 3×35+25 = 130
HOPE IT HELPS YOU!!!
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