angle b=90 degree find sin a cos c ac=13 bc=5 ab=? find ab also pls
it is concise mathematics i cse
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△ ABC is a right-angled triangle.
By Pythagoras theorem,
AC^2 = BC^2 + AB^2
⇒13^2 = 5^2 + AB^2
⇒AB^2 =−(5)^2 +13^2
⇒AB^2 = −25+169
⇒AB^2 = 144
⇒AB= √144
⇒AB=12 cm.
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