Question

Angle b equal to 90 degrees BD perpendicular to AC prove that BC square by AB square is equal to DC by AD

Answer 1

Answer:

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this is your correct answer

Answer 2

$\frac{BC^2}{AB^2}= \frac{DC}{AD}$

Step-by-step explanation:

in triangle ADB and ADC

$\angle A = \angle A$ (common)

$\angle ABC = \angle ADB= 90^\circ\\\\\bigtriangleup ADB \sim \bigtriangleup ABC\\\\\frac{AD}{AB}=\frac{AB}{AC}\\\\\text{cross multiplying we get}\\\\AB^2=AC.AD\\\\similarly \\\\\bigtriangleup BDC \sim \bigtriangleup ABC\\\\\frac{DC}{BC}=\frac{BC}{AC}\\\\\text{cross multiplying we get}\\\\BC^2=AC.DC$

now , dividing  $AB^2=AC.AD...1 ,BC^2=AC.DC..2$ we get

$\frac{BC^2}{AB^2}= \frac{DC}{AD}$

hence , proved

#Learn more:

ABC BAC= 90 degree and AD parallel BC prove that ad square is equal to BD X DC​

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