Question

angle b is 90 degree angle a is 30 degree ac is 10cm then find ab and bc​

Answer 1

Answer:

Given -: angle ABC = 90°

angle BAC = 30°

=> angle ACB = 90 - 30 = 60°

AC = 10 cm.

to find -: AB & BC

solution -: sin ( angle ACB ) = AB / AC

=> Sin 60° = AB / 10

=> √3 / 2 = AB / 10

=> AB = 5√3 cm.

Cos ( angle ACB ) = BC / AC

=> COS 60° = BC / 10

=> 1 / 2 = BC / 10

=> BC = 5 cm.

AB = 5√3 cm. & BC = 5cm.