Math, asked by KushalKumar4487, 1 year ago

angle BCD is an exterior angle of triangle ABC if angle BCD= 3x,angle A=x and angle B =80 .gind the calue of x

Answers

Answered by aliciav
14
Angle BCD = angle A + angle B (exterior angle property)

3x = x + 80
80 = 2x
x = 40
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