Angle between 2i+3j+k and -3i+6k
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A = 2i + 3j + k
B = -3i + 6k
|A| = sqrt(4 + 9 + 1) = sqrt(14)
|B| = sqrt(9 + 36) = sqrt(45)
A.B = |A||B|cosθ
(-6 + 6) = sqrt(14 × 45) cosθ
0 = sqrt(630) cosθ
cosθ = 0
θ = 90°
Angle between given vectors is 90°
B = -3i + 6k
|A| = sqrt(4 + 9 + 1) = sqrt(14)
|B| = sqrt(9 + 36) = sqrt(45)
A.B = |A||B|cosθ
(-6 + 6) = sqrt(14 × 45) cosθ
0 = sqrt(630) cosθ
cosθ = 0
θ = 90°
Angle between given vectors is 90°
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