Angle between 3i+2j+k and 6i+ 4j+ 2k
Answers
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3 November k
a bi bus mein a jaaiye
Answered by
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Answer:
according to the concept of dot product
(3i+2j+k).(6i+4j+2k )=18+8+2=28
Explanation:
now, cosA =a . b /[a] [b]=cos-128/28=cos-1(1)= 0 degree
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