angle between i+j and i+k is
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from dot product of two vectors
cos@ = a.b/|a||b|.
a= i+j |a|= √2. a.b=(i+j).(i+k)=1
b=i+k |b|= √2
cos@= 1/(√2)(√2) =1/2
@=π/3=60*
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