Angle between incident ray and reflected ray is 90o
. Find the values of angle of incidence and angle of reflection?
Draw the ray diagram for the described case and state the nature of image formed: Object is placed between C
and F of a concave mirror
pls answer and dont copy and text pls
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Here we find the incident ray is making an angle of 90 degree with that of the reflected ray , so the incident ray is making an angle 90 ÷2 degree with the angle of incidence is 45 degrees i.e (normal bisects the angle between the incident ray and the reflected ray of light .)
When a ray of light is incident normally on a plane mirror it means that the angle of incidence is 0ₒ. From the law of reflection, we find that angle of reflection is also 0. Thus, for normal incidence on a plane mirror, angle of incidence and angle of reflection are 0ₒ.
Hence a real, inverted and same size image is formed at center of curvature.
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