Question

Angle between lines V3x + y + 16 = 0 and V3x – y +9 = 0
is =
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Answer 1

Answer:

• Given is :
• line A √3x+y+16= 0

B √3x-y+9 =0

• prove that

Angle between line A and B

so

write in the form y=mx+c

y= -(16+√3x) & y= 3x+9

m1 = -√3 m2 = √3

tan(A−B)= 1+tanAtanB/tanA−tanB

tan(A-B)= 1-3/0 = infinite

so Angle between A and B is 90⁰