Question

angle between pair of tangent from (5/3,-5/3) to circle x2+y2=5​

Answer 1

Step-by-step explanation:

Here, S=3x

2

+2y

2

−5=0

S

1

=3(1)

2

+2(2)

2

−5=3+8−5=6

[∵ Point (1,2)]

T=3x⋅x

1

+2y⋅y

1

−5

=3x(1)+2y(2)−5

=3x+4y−5

Now, use, SS

1

=T

2

(3x

2

+2y

2

−5)⋅6=(3x+4y−5)

2

18x

2

+12y

2

−30=9x

2

+16y

2

+24xy+25−30x−40y

⇒9x

2

−4y

2

−24xy+30x+40y−55=0

Here, a=9,b=−4 and h=−12

∴tanθ=

a+b

2

h

2

−ab

=

9−4

2

144+36

=

5

2

180

=

5

6

20

=

5

12

.

Answer 2

$\large\colorbox{cyan}{Answer✓}$

12 is your answer...