angle between two vectors a and bu iş theta then angle between 2a and - b/2
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Answer:
ANSWER
tan
2
θ
=
A+Bcosθ
Bsinθ
=
A+B(2cos
2
2
θ
−1)
B(2×sin
2
θ
cos
2
θ
)
Atan
2
θ
+B(2cos
2
2
θ
−1)×tan
2
θ
=2Bsin
2
θ
cos
2
θ
Atan
2
θ
+2Bcos
2
θ
sin
2
θ
−Btan
2
θ
=2Bsin
2
θ
cos
2
θ
⇒Atan
2
θ
=Btan
2
θ
A=B
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