Angle between two vectors A=i-j and B=j+k is
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Use A.B = magnitude of A multiply by Magnitude of B multiply by cosQ
Here A.B is dot product of a and b
Calculate magnitude by root over Asquare + Bsquare
Here A.B is dot product of a and b
Calculate magnitude by root over Asquare + Bsquare
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Answer:
cos theta =a.b/|a| |b|
a=i-j =i-j+0k
b=j=k=0i+j+k
(i-j+0kO.(0i+j+k)/Root 1 square+1 square
-1/root 2 x root 2=-1/root 2
Explanation:
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