angle between x=9 and x-✓3y +7=0
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Answers
Answered by
0
Answer:
3x+y−7=0 and x+2y+9=0
write in the form y=mx+c
i.e.y=−3x+7,y= -x/2 - 9/2
m
1
=−3 and m
2
∓−
2
1
tan(A−B)=
∣
∣
∣
∣
∣
1+tanAtanB
tanA−tanB
∣
∣
∣
∣
∣
∣
∣
∣
∣
∣
1+(−3)(−y
2
)
−3−(−y
2
)
∣
∣
∣
∣
∣
=
∣
∣
∣
∣
∣
5/2
−5/2
∣
∣
∣
∣
∣
=1
∴ Angle b/w then is tan
−1
(1)=45
∘
=
4
π
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Answered by
3
Answer:
π/6
Step-by-step explanation:
Angle between lines = tan-¹|(m+n)/1+mn|
m and n being the slopes of the lines given
m = 0 [for x - 9 = 0]
finding n:
x - √3y + 7 = 0
→ y = 1/√3 x + 7
→ n = dy/dx = 1/√3
Angle = tan-¹ |0+1/√3)/1+0| = tan-¹ 1/√3 = π/6
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