Angle bisectors AX and BY of triangle ABC meet at point I. Find angle C, in degrees, if angle AIB = 109. Thank you! Please help! It is due today!
[asy]
pair A,B,C,X,Y,I;
A= (0,0);
B = (1,0);
C = (0.6,0.5);
X = intersectionpoint(B--C , A -- (bisectorpoint(B,A,C)));
Y = intersectionpoint(A--C, B -- scale(6)*( (bisectorpoint(C,B,A)) - B));
I = intersectionpoint(A--X, B--Y);
draw(X--A--C--B--Y);
draw(A--B);
label("$A$",A,SW);
label("$B$",B,SE);
label("$C$",C,N);
label("$I$",I,S);
label("$X$",X,NE);
label("$Y$",Y,NW);
[/asy]
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