Angle cab=25° find angle bdc,angle dba and anglecob
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∠BDC = 25° , ∠DBA = 65° & ∠COB = 50° if in given fig ∠CAB = 25°
Step-by-step explanation:
∠CAB = 25° ( Given)
∠BDC = ∠CAB as both the angles are subtended by Chord BC
=> ∠BDC = 25°
in ΔDBP
∠DBP + ∠BDP + ∠BPD = 180°
∠DBP = ∠DBA
∠BDP = ∠BDC = 25°
∠BPD = 90°
=> ∠DBA + 25° + 90° = 180°
=> ∠DBA = 65°
∠COB = 2∠CAB = 2 ∠BDC ( angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.)
=> ∠COB = 2 * 25°
=> ∠COB = 50°
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