Angle for throw of any projectile to achieve maximum vertical range
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Answered by
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The angle for getting maximum vertical range is 90°.
Thanks for asking
Hope it will help
Thanks for asking
Hope it will help
sharmin1098765:
As for vertical range.. wouldn't it be 90°???
see in order to attain a maximum height the value of angle should be maximum which in this case is +1 which comes at 90°
and in case of range it becomes sin 2angle which at 45° becomes 90
That's right. Max vertical range indicates the max height right?? Because it's "vertical" not horizontal...
yes
Answered by
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I think it is 45° for max vertical range.
bcz range=u^2sin2theta
then sin2theta=sin90°
bcz range=u^2sin2theta
then sin2theta=sin90°
It said "vertical" range.. not horizontal, right?
ohh i didn't see
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