Question

\angle \mathrm{ACD} \text { is an exterior angles of } \Delta \mathrm{ABC} \text { . If } \angle \mathrm{ACD}=130^{\circ}, \angle \mathrm{A}=55^{\circ}, \text { then } \angle \mathrm{B}=∠ACD is an exterior angles of ΔABC . If ∠ACD=130
∘
,∠A=55
∘
, then ∠B= __________​

Answer 1

Answer:

hey mate your answer is 75

Step-by-step explanation:

Hope it helps....130=55+75

It is exterior angle property