Question

Angle oab=30
Find angle acb,angle abo,angle COD,angle BOC
ABCD is a rectangle

Answer 1

Answer:

In AABC,

> ZCAB + LABC + ZACB = 180°.

+ 30° + 90° + ZACB = 180°.

» 120° + ZACB = 180°.

.. ZACB = 60°

We know that, diagonals of rectangle are equal and bisect each other equally.

. AO = 0 C = B0 = OD

In AABO,

AO=BO

+ ZOAB = ZABO [Angle opposite to

equal side are also equal ]

=> ZOAB = ZABO = 30°

+ ZOAB ZABO + BOA = 180°

> 30° + 30° + ZBOA= 180°.

ZBOA= 120°.

ZBOA = ZCOD [Vertically opposite

angle]

. ZCOD = 120°

> ZCOD + ZBOC = 180°

> 120° + ZBOC = 180°

... ZBOC= 60°.

[Linear pair ]

» ZACB = 60°, ZABO = 30°, ZCOD =

120° and ZBOC = 60°.