angle of a quadrilateral are 5 x + 50° 4 x + 1 60° angle 6 + 60 degree angle 3 y + 100° write a linear equation which satisfies these data
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The sum of four angles of a quadrilateral = 5x-30+3x+60+60-x+4x+50 = 360⁰
Or, 5x+3x-x+4x-30+60+60+50 = 360
Or, 11x+140 = 360
Or, 11x = 360–140
Or, 11x = 220
Or, x = 220/11
Or, x = 20
The angles are
5x-30 = 5×20-30 = 100-30 = 70⁰
3x+60 = 3×20+60 = 60+60 = 120⁰
60-x = 60 – 20= 40⁰
4x+50 = 4×20+50 = 80+50 = 130
The smallest angle = 60-x = 60 – 20= 40⁰
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