Question

angle of a qudrilateral are in ratio 3x 4 x5x 6x ​

Answer 1

Step-by-step explanation:

Given that angles of a quadrilateral are in the ratio 3 : 4: 5 : 6 .Let the angle be 3x , 4x , 5x , 6x

3x+4x+5x+6x=360o

⇒x=18360o

⇒x=20o

Therefore the angles are

3×20=60o

4×20=80o

5×20=100o

6×20=120o

Since all the angles are different degrees thus from as trapezium

Answer 2

$\mathbb{\underline{ \underline{Given:- }}}$

$• \: \sf{Angle \: of \: a \: qudrilateral \: are \: in \: ratio \: 3: 4 : 5 : 6 }$

$\mathbb{\underline{ \underline{To \: Find :- }}}$

$\sf• \: The \: angles \: of \: the \: quadrilateral.$

$\mathbb{\underline{ \underline{ Solution :-}}}$

$\sf Let \: the \: constant \: be \: x$

$\sf{So, \: the \: angles \: are \: respectively \: 3x \: , 4x \: ,5x \: ,6x \: .}$

$\sf{We \: know \: that, \: the \: sum \: of \: the \: four \: angles \: of \: a \: quadrilateral \: is \: 360°.}$

$\sf{According \: to \: the \: question, }$

$\sf3x + 4x + 5x + 6x = 360 \degree$

$\sf⇒18x = 360 \degree$

$\sf⇒ x= \frac{360 \degree}{18}$

$\sf⇒x = 20 \degree$

$\therefore \sf1st \: angle =( 3 \times 20) \degree = 60 \degree$

$\therefore \sf2nd \: angle =( 4 \times 20) \degree = 80 \degree$

$\therefore \sf3rd \: angle =( 5\times 20) \degree =10 0 \degree$

$\therefore \sf4th \: angle =( 6\times 20) \degree =12 0 \degree$

$\sf \red{Hence, \: the \: angles \: of \: the \: quadrilateral \: are \: respectively } \\ \sf \red{60°, 80°, 100° \: and \: \: 120°.}$