Physics, asked by preeti2657, 11 months ago

Angle of deviation (δ) by a prism (refractive index
= μ and supposing the angle of prism A to be
small) can be given by
(a) δ = (μ -1)A (b) δ = (μ +1) A
(c) δ = sin A + δ (d) δ = (μ -1) A
2 (μ +1)
sin A
2

Answers

Answered by Kannan0017
0

Explanation:

(a) delta=(mue-1)A

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