Chemistry, asked by patildhiru553, 11 months ago

angle of deviation in cyclo butane is????​

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Answered by Anonymous
1

Answer:

The bond angle in cyclobutane is 90˚. The normal tetrahedral bond angle value is 109.5˚. That is why, deviation = (normal tetrahedral bond angle) – (actual bond angle) • Deviation = 109˚ 5' – 90 = 19.5˚. Deviation for cyclopropane is 49.5˚ • Deviation for cyclobutane is 19.5˚..

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