angle of deviation in cyclo butane is????
Answers
Answered by
1
Answer:
The bond angle in cyclobutane is 90˚. The normal tetrahedral bond angle value is 109.5˚. That is why, deviation = (normal tetrahedral bond angle) – (actual bond angle) • Deviation = 109˚ 5' – 90 = 19.5˚. Deviation for cyclopropane is 49.5˚ • Deviation for cyclobutane is 19.5˚..
I hope it will help you.
Plzz mark my answer as brainlist.
Plzz follow me freind
Similar questions
Math,
5 months ago
Physics,
5 months ago
Art,
9 months ago
CBSE BOARD X,
9 months ago
English,
1 year ago