Question

Angle of elevation of a tree 80m away is 12°5'. What is the height of the tree?​

Answer 1

Answer:

Height of Tree = 17.12 m

Explanation:

the angle of elevation of a tree at a place 80 m away is 12° 5'. What is the height of

the tree?

Tana = Perpendicular / Base

a = 12°5' = (12.0833°)

Pependicular = Height of tree

Base Distnace of Tree = 80 m

Tan(12.0833°) = Height of Tree/80 => Height of Tree 80 * 0.214

=> Height of Tree = 17.12 m