angle of elevation of cloud. is from 30m above a lake. It was olaserved that m the of a of 45 e a beench up in 200 from the same poluor the angle of . de of gebraciones en thee ugensation of course is loks clouod ich is found to be boo find the height of the og cloud . f from lake.
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Answer:
Solution:
In ΔABC
tan30
∘
=
x
h
x = h
3
i)
In ΔBDC
tan60
∘
=
x
h+400
3
x=h+400 .(ii)
from (i) and (ii)
h
3
.
3
=h+400
3h - h = 400
h =
2
400
=200
h = 200
So, height of object above the lake = h + 200 = 200 + 200 = 400m
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