Math, asked by smitadahiya0, 5 days ago

angle of elevation of cloud. is from 30m above a lake. It was olaserved that m the of a of 45 e a beench up in 200 from the same poluor the angle of . de of gebraciones en thee ugensation of course is loks clouod ich is found to be boo find the height of the og cloud . f from lake.​

Answers

Answered by 812344
0

Answer:

Solution:

In ΔABC

tan30

=

x

h

x = h

3

i)

In ΔBDC

tan60

=

x

h+400

3

x=h+400 .(ii)

from (i) and (ii)

h

3

.

3

=h+400

3h - h = 400

h =

2

400

=200

h = 200

So, height of object above the lake = h + 200 = 200 + 200 = 400m

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