Question

Angle of elevation of the top of a 60 meters tall tower from a point x on a level ground is 30 degree. what is the approximate distance between the point x and the base of the tower ?

Answer 1

Step-by-step explanation:

tan30= opposite/adjacent

tan30 =60/adjacent

then put value of tan 30 and cross multiple, simplyfy you will get answer

Answer 2

The approximate distance between the point x and the base of the tower is 60√3 m or 103.92 m.

Step-by-step explanation:

The height of the tall tower = 60 m

The angle of elevation from the point X to the top of the tower = 60°  

Let the distance between the point X and the base of the tower be “BX”. (as shown in the figure attached below)

Now, applying the trigonometry property of triangles in ∆ ABX, we have

tan θ = $\frac{perpendicular}{base} = \frac{AB}{BX}$

⇒ tan 60° = $\frac{60}{BX}$

⇒ $\frac{1}{\sqrt{3}} = \frac{60}{BX}$

⇒ BX = 60√3 m or 103.92 m

Thus, the approximate distance between the point x and the base of the tower is 60√3 m or 103.92 m.

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