Question

angle of elevation of the top of a tower from a point is 30 degree. If the observer moves a distance of 20 m towards the tower to the angle of elevation increases to 15. Find the height of tower.​

Answer 1

$━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━</p><p></p><p>[tex] \bf \red{Answer}$

$\bf \scriptsize{Given - A \: line \: segments \: AB \: = 6.4 \: cm}$

$\bf \scriptsize{Required- To \: construct \: a \: perpendicular \: bisector \: CD.}$

$\bf \red{Step \: Of \: construction :}$

$\bf \scriptsize{Step1 .) Draw \: a \: line \: segment \: AB \: = 6.4 cm. \: }$

$\bf \scriptsize \: {Step 2.)With \: A \: as \: centre \: and \: radius \: greater \: than \: AB \: , draw \: two \: arcs \: , one \: on \: either } \\ \bf \scriptsize { side \: of \: line \: segments \: AB.}$

$\bf \scriptsize{Step \: 3.)With \: centre \: B \: and \: the \: same \: radius \: as \: in \: step \: 2 draw \: two \: arcs \: , intersecting \: the \: arcs} \\ \bf \scriptsize{drawn \: in \: Step \: 2 \: at \: C \: and \: D.}$

$\bf \scriptsize{Step \: 4.)Join \: C \: and \: D . Line \: segment \: CD \: bisects \: AB \: at \: L.} \\ </p><p></p><p>━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━$

Answer 2

p><p></p><p>[tex]Answer

\bf \scriptsize{Given - A \: line \: segments \: AB \: = 6.4 \: cm}Given−AlinesegmentsAB=6.4cm

\bf \scriptsize{Required- To \: construct \: a \: perpendicular \: bisector \: CD.}Required−ToconstructaperpendicularbisectorCD.

\bf \red{Step \: Of \: construction :}StepOfconstruction:

\bf \scriptsize{Step1 .) Draw \: a \: line \: segment \: AB \: = 6.4 cm. \: }Step1.)DrawalinesegmentAB=6.4cm.

\begin{gathered} \bf \scriptsize \: {Step 2.)With \: A \: as \: centre \: and \: radius \: greater \: than \: AB \: , draw \: two \: arcs \: , one \: on \: either } \\ \bf \scriptsize { side \: of \: line \: segments \: AB.}\end{gathered}

Step2.)WithAascentreandradiusgreaterthanAB,drawtwoarcs,oneoneither

sideoflinesegmentsAB.

\begin{gathered} \bf \scriptsize{Step \: 3.)With \: centre \: B \: and \: the \: same \: radius \: as \: in \: step \: 2 draw \: two \: arcs \: , intersecting \: the \: arcs} \\ \bf \scriptsize{drawn \: in \: Step \: 2 \: at \: C \: and \: D.}\end{gathered}

Step3.)WithcentreBandthesameradiusasinstep2drawtwoarcs,intersectingthearcs

drawninStep2atCandD.

\begin{gathered} \bf \scriptsize{Step \: 4.)Join \: C \: and \: D . Line \: segment \: CD \: bisects \: AB \: at \: L.} \\ < /p > < p > < /p > < p > ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━\end{gathered}

Step4.)JoinCandD.LinesegmentCDbisectsABatL.

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