Question

Angle of elevation of the top of a tower from a point on the ground which is 30 metre away from the foot of the tower is 30 degree find the height of the tower

Answer 1

Answer:    Hence he height of the tower is 17.32 meters.

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

Suppose the height of the tower is h.

The distance from the foot of the tower is given as 30 meters.

The angle of elevation of top of the tower is 30 degrees.

Using SOH CAH TOA

$tan30=\frac{opposite}{adjacent}$

$tan30=\frac{h}{30}$

$h=30tan30$

Plugging the value of tan 30

$h=17.32$ meters

Hence he height of the tower is 17.32 meters.  :   Answer

Hope it will help :)

Answer 2

Answer:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.