angle of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it a complementary prove that its height of tower is 6 m
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∠C and ∠D are complementary
9AB==AB7
Put value of tanQ in eqn (ii)
∴BCAB=AB9
AB2=9BC
AB=36=6
Height of tower =6m
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