angle of elevation of the top of the hill at the foot of the tower is 60 degrees and the angle of elevation of the top of the tower from the foot of the hill is 30 degrees. if the tower is 50m high what is the height of the hill?
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angle of elevation of the hill at the foot of the tower = 60
angle of elevation of the top of the tower from the foot of the hill= 30
height of the tower= 50m
tan theta = opposite/adjacent
tan 30 = 50/BC = 1/√3
BC = 50√3.............1
tan theta= opposite/adjacent
tan 60 = ab / 50√3 = √3
ab = 50×3
ab = 150
therefore, the height of the hill is 150
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