Question

angle of elevation of the top of the tower from one point on the ground which is 30 metre away from the foot of the tower is 30 degree find the height of the tower​

Answer 1

$\tan(30) = \frac{opposite}{adjacent}$

$\tan(30) = \frac{1}{ \sqrt{3} }$

$\frac{1}{ \sqrt{3} } = \frac{opposite}{30}$

$\frac{10 \times 3}{ \sqrt{3} } = opposite$

$\boxed{the\: height \:of \:building\: is \:10√3}$

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Answer 2

your answer is in picture.

hope this will help you ;) :) ....