Question

angle of incident is 45 degree and the angle of refraction is 30 degree . calculate the refractive index of second medium with respect to first medium​

Answer 1

Using snell's law

$\sin(i) \div \sin(r) = \gamma$

$here \: \: \: \gamma = refractive \: index$

$\gamma = \sin(45) \div \sin(30)$

1/v2÷1/2

v= root

$\gamma = 2 \div \sqrt{2}$

$\gamma = 2 \div 1.414 = 1.414$

thus refractive index is 1.414