Question

angle of incident of a Ray of light is 45 degree if a Ray of a light travel from area to glass find the area angle of reflection reflective index of Glass is CUG is equal to 1.5​

Answer 1

Given that:-

$\large\rm { \angle i = 45^{\circ}}$

$\large\rm{ ^{a} u_{g} = 1.5}$

To find:-

$\large\rm { \angle r}$

Formula used:-

$\large\rm{ ^{a} u_{g} = \frac{ \sin \ i}{ \sin \ r}}$

Solution:-

$\large\rm{ ^{a} u_{g} = 1.5}$

$\large\rm{ ^{a} u_{g} = \frac{ \sin \ i}{ \sin \ r}}$

$\large\rm{ \therefore \sin \ r = \frac{ \sin \ i}{^{a} u_{g}}}$

$\large\rm { = \frac{ \sin 45}{1.52}}$

$\large\rm{ = \frac{0.709}{1.52}}$

$\large\rm{ = 0.46}$

$\huge{\boxed{\rm { \angle r = \sin ^{-1} 0.46}}}$