Question

Angle of internal friction of a purely cohesive soil

Answer 1

Hey mate!

Here's your answer!!

➡ The angle of internal friction is the angle (φ), measured between the normal force (N) and resultant force (R), that is attained when failure just occurs in response to a shearing stress (S).


➡ And the angle of internal friction of a purely cohensive soil is the strength parameters of soils.

➡ It is used to define the shear friction resistance of soils together with the normal effective stress.

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Answer 2

Answer:

The angle of internal friction of purely cohesive soil is zero degree$(0^{\circ})$.

Explanation:

internal friction (IF) is that the force-resisting motion between the weather making up a solid material while it undergoes deformation.

The angle of internal friction could be a property of earth materials or the slope of a linear representation of the shear strength of earth materials.

The shear strength of soil specimens as per Mohr and Columbus Criterion is given by $\tau=C+\sigma \tan \phi$

Where $C=$Cohesion and $\phi$ is that the angle of internal friction and these both are called shear strength parameters. These shear strength parameters can only be determined experimentally using the triaxial test.

$\sigma$ is that the total stress at the given point.

For pure sand, $C=0$ and $\phi \neq 0$.

For pure clay, $C \neq 0$ and $\phi=0$

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